Consider the following three equations:
x0 + 2 * x1 + x2 = 4
x1 + x2 = 3
x0 + x2 = 5
We can express this system as a matrix equation A * x = b with:
A = np.array([[1, 2, 1],
[0, 1, 1],
[1, 0, 1]])
b = np.array([4, 3, 5])
Then, use np.linalg....
Least squares is a standard approach to problems with more equations than unknowns, also known as overdetermined systems.
Consider the four equations:
x0 + 2 * x1 + x2 = 4
x0 + x1 + 2 * x2 = 3
2 * x0 + x1 + x2 = 5
x0 + x1 + x2 = 4
We can express this as a matrix multiplication A * x = b:
A ...
