Tutorial by Topics: overload

The process of overload resolution is described in the C# specification, section 7.5.3. Also relevant are the sections 7.5.2 (type inference) and 7.6.5 (invocation expressions). How overload resolution works will probably be changed in C# 7. The design notes indicate that Microsoft will roll out ...
Integer Literals is a numeral without a decimal point for example 0, 1, 42, ... is implicitly applied to fromInteger which is part of the Num type class so it indeed has type Num a => a - that is it can have any type that is an instance of Num Fractional Literals is a numeral with a ...
See also separate topic on Overload Resolution Ambiguities can occur when one type can be implicitly converted into more than one type and there is no matching function for that specific type. For example: void foo(double, double); void foo(long, long); //Call foo with 2 ints foo(1, 2);...
In C++, it is possible to define operators such as + and -> for user-defined types. For example, the <string> header defines a + operator to concatenate strings. This is done by defining an operator function using the operator keyword. The operators for built-in types cannot be change...
Overload resolution happens in several different situations Calls to named overloaded functions. The candidates are all the functions found by name lookup. Calls to class object. The candidates are usually all the overloaded function call operators of the class. Use of an operator. The candid...
A normal function is never related to a function template, despite same name, same type. A normal function call and a generated function template call are different even if they share the same name, same return type and same argument list
Most operators in Rust can be defined ("overloaded") for user-defined types. This can be achieved by implementing the respective trait in std::ops module.

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