arduino Interrupts Interrupt on Button Press
Example
This example uses a push button (tact switch) attached to digital pin 2 and GND, using an internal pull-up resistor so pin 2 is HIGH when the button is not pressed.
const int LED_PIN = 13;
const int INTERRUPT_PIN = 2;
volatile bool ledState = LOW;
void setup() {
pinMode(LED_PIN, OUTPUT);
pinMode(INTERRUPT_PIN, INPUT_PULLUP);
attachInterrupt(digitalPinToInterrupt(INTERRUPT_PIN), myISR, FALLING); // trigger when button pressed, but not when released.
}
void loop() {
digitalWrite(LED_PIN, ledState);
}
void myISR() {
ledState = !ledState;
// note: LOW == false == 0, HIGH == true == 1, so inverting the boolean is the same as switching between LOW and HIGH.
}
One gotcha with this simple example is that push buttons tend to bounce, meaning that when pressing or releasing, the circuit opens and closes more than once before it settles into the final closed or open state. This example doesn't take that into account. As a result, sometimes pressing the button will toggle the LED multiple times, instead of the expected once.
