Example
arr = np.arange(10).reshape(2, 5)
Using .transpose method:
arr.transpose()
# Out:
# array([[0, 5],
# [1, 6],
# [2, 7],
# [3, 8],
# [4, 9]])
.T method:
arr.T
# Out:
# array([[0, 5],
# [1, 6],
# [2, 7],
# [3, 8],
# [4, 9]])
Or np.transpose:
np.transpose(arr)
# Out:
# array([[0, 5],
# [1, 6],
# [2, 7],
# [3, 8],
# [4, 9]])
In the case of a 2-dimensional array, this is equivalent to a standard matrix transpose (as depicted above). In the n-dimensional case, you may specify a permutation of the array axes. By default, this reverses array.shape:
a = np.arange(12).reshape((3,2,2))
a.transpose() # equivalent to a.transpose(2,1,0)
# Out:
# array([[[ 0, 4, 8],
# [ 2, 6, 10]],
#
# [[ 1, 5, 9],
# [ 3, 7, 11]]])
But any permutation of the axis indices is possible:
a.transpose(2,0,1)
# Out:
# array([[[ 0, 2],
# [ 4, 6],
# [ 8, 10]],
#
# [[ 1, 3],
# [ 5, 7],
# [ 9, 11]]])
a = np.arange(24).reshape((2,3,4)) # shape (2,3,4)
a.transpose(2,0,1).shape
# Out:
# (4, 2, 3)
