Algorithm
This algorithm is a two step process.First we create a auxiliary array lps[] and then use this array for searching the pattern.
Preprocessing :
Searching
We keep matching characters txt[i] and pat[j] and keep incrementing i and j while pat[j] and txt[i] keep matching.
When we see a mismatch,we know that characters pat[0..j-1] match with txt[i-j+1…i-1].We also know that lps[j-1] is count of characters of pat[0…j-1] that are both proper prefix and suffix.From this we can conclude that we do not need to match these lps[j-1] characters with txt[i-j…i-1] because we know that these characters will match anyway.
Implementaion in Java
public class KMP {
public static void main(String[] args) {
// TODO Auto-generated method stub
String str = "abcabdabc";
String pattern = "abc";
KMP obj = new KMP();
System.out.println(obj.patternExistKMP(str.toCharArray(), pattern.toCharArray()));
}
public int[] computeLPS(char[] str){
int lps[] = new int[str.length];
lps[0] = 0;
int j = 0;
for(int i =1;i<str.length;i++){
if(str[j] == str[i]){
lps[i] = j+1;
j++;
i++;
}else{
if(j!=0){
j = lps[j-1];
}else{
lps[i] = j+1;
i++;
}
}
}
return lps;
}
public boolean patternExistKMP(char[] text,char[] pat){
int[] lps = computeLPS(pat);
int i=0,j=0;
while(i<text.length && j<pat.length){
if(text[i] == pat[j]){
i++;
j++;
}else{
if(j!=0){
j = lps[j-1];
}else{
i++;
}
}
}
if(j==pat.length)
return true;
return false;
}
}