The easiest and quickest way to encode a Haskell data type to JSON with Aeson is using generics.
{-# LANGUAGE DeriveGeneric #-}
import GHC.Generics
import Data.Text
import Data.Aeson
import Data.ByteString.Lazy
First let us create a data type Person:
data Person = Person { firstName :: Text
, lastName :: Text
, age :: Int
} deriving (Show, Generic)
In order to use the encode
and decode
function from the Data.Aeson
package we need to make Person
an instance of ToJSON
and FromJSON
. Since we derive Generic
for Person
, we can create empty instances for these classes. The default definitions of the methods are defined in terms of the methods provided by the Generic
type class.
instance ToJSON Person
instance FromJSON Person
Done! In order to improve the encoding speed we can slightly change the ToJSON
instance:
instance ToJSON Person where
toEncoding = genericToEncoding defaultOptions
Now we can use the encode
function to convert Person
to a (lazy) Bytestring:
encodeNewPerson :: Text -> Text -> Int -> ByteString
encodeNewPerson first last age = encode $ Person first last age
And to decode we can just use decode
:
> encodeNewPerson "Hans" "Wurst" 30
"{\"lastName\":\"Wurst\",\"age\":30,\"firstName\":\"Hans\"}"
> decode $ encodeNewPerson "Hans" "Wurst" 30
Just (Person {firstName = "Hans", lastName = "Wurst", age = 30})