R Language Intervals, Durations and Periods


Example

Intervals are simplest way of recording timespans in lubridate. An interval is a span of time that occurs between two specific instants.

# create interval by substracting two instants
today_start <- ymd_hms("2016-07-22 12-00-00", tz="IST")
today_start
## [1] "2016-07-22 12:00:00 IST"
today_end <- ymd_hms("2016-07-22 23-59-59", tz="IST")
today_end
## [1] "2016-07-22 23:59:59 IST"
span <- today_end - today_start
span
## Time difference of 11.99972 hours
as.interval(span, today_start)
## [1] 2016-07-22 12:00:00 IST--2016-07-22 23:59:59 IST

# create interval using interval() function
span <- interval(today_start, today_end)
[1] 2016-07-22 12:00:00 IST--2016-07-22 23:59:59 IST

Durations measure the exact amount of time that occurs between two instants.

duration(60, "seconds")
## [1] "60s"

duration(2, "minutes")
## [1] "120s (~2 minutes)"

Note: Units larger than weeks are not used due to their variability.

Durations can be created using dseconds, dminutes and other duration helper functions.
Run ?quick_durations for complete list.

dseconds(60)
## [1] "60s"

dhours(2)
## [1] "7200s (~2 hours)"

dyears(1)
## [1] "31536000s (~365 days)"

Durations can be subtracted and added to instants to get new instants.

today_start + dhours(5)
## [1] "2016-07-22 17:00:00 IST"

today_start + dhours(5) + dminutes(30) + dseconds(15)
## [1] "2016-07-22 17:30:15 IST"

Durations can be created from intervals.

as.duration(span)
[1] "43199s (~12 hours)"

Periods measure the change in clock time that occurs between two instants.

Periods can be created using period function as well other helper functions like seconds, hours, etc. To get a complete list of period helper functions, Run ?quick_periods.

period(1, "hour")
## [1] "1H 0M 0S"

hours(1)
## [1] "1H 0M 0S"

period(6, "months")
## [1] "6m 0d 0H 0M 0S"

months(6)
## [1] "6m 0d 0H 0M 0S"

years(1)
## [1] "1y 0m 0d 0H 0M 0S"

is.period function can be used to check if an object is a period.

is.period(years(1))
## [1] TRUE

is.period(dyears(1))    
## [1] FALSE