Swift Language Access Control Basic Example using a Struct
Example
3.0
In Swift 3 there are multiple access-levels. This example uses them all except for open:
public struct Car {
public let make: String
let model: String //Optional keyword: will automatically be "internal"
private let fullName: String
fileprivate var otherName: String
public init(_ make: String, model: String) {
self.make = make
self.model = model
self.fullName = "\(make)\(model)"
self.otherName = "\(model) - \(make)"
}
}
Assume myCar was initialized like this:
let myCar = Car("Apple", model: "iCar")
Car.make (public)
print(myCar.make)
This print will work everywhere, including targets that import Car.
Car.model (internal)
print(myCar.model)
This will compile if the code is in the same target as Car.
Car.otherName (fileprivate)
print(myCar.otherName)
This will only work if the code is in the same file as Car.
Car.fullName (private)
print(myCar.fullName)
This won't work in Swift 3. private properties can only be accessed within the same struct/class.
public struct Car {
public let make: String //public
let model: String //internal
private let fullName: String! //private
public init(_ make: String, model model: String) {
self.make = make
self.model = model
self.fullName = "\(make)\(model)"
}
}
If the entity has multiple associated access levels, Swift looks for the lowest level of access. If a private variable exists in a public class, the variable will still be considered private.
