Microsoft SQL Server Modify JSON text Insert single JSON object generated with FOR JSON clause
Example
You can generate JSON object using standard SELECT query with FOR JSON clause and WITHOUT_ARRAY_WRAPPER option, and insert it into JSON text as a third parameter:
declare @json nvarchar(4000) = N'{"Id":17,"Name":"WWI"}'
set @json = JSON_MODIFY(@json, '$.table',
JSON_QUERY(
(select name, create_date, schema_id
from sys.tables
where name = 'Colors'
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER)))
print @json
(1 row(s) affected)
{"Id":17,"Name":"WWI","table":{"name":"Colors","create_date":"2016-06-02T10:04:03.280","schema_id":13}}
FOR JSON with WITHOUT_ARRAY_WRAPPER option may generate invalid JSON text if SELECT query returns more than one result (you should use TOP 1 or filter by primary key in this case). Therefore, JSON_MODIFY will assume that returned result is just a plain text and escape it like any other text if you don't wrap it with JSON_QUERY function.
You should wrap FOR JSON, WITHOUT_ARRAY_WRAPPER query with JSON_QUERY function in order to cast result to JSON.
