python -m SimpleHTTPServer 9000
python -m http.server 9000
Running this command serves the files of the current directory at port 9000
.
If no argument is provided as port number then server will run on default port 8000
.
The -m
flag will search sys.path
for the corresponding .py
file to run as a module.
If you want to only serve on localhost you'll need to write a custom Python program such as:
import sys
import BaseHTTPServer
from SimpleHTTPServer import SimpleHTTPRequestHandler
HandlerClass = SimpleHTTPRequestHandler
ServerClass = BaseHTTPServer.HTTPServer
Protocol = "HTTP/1.0"
if sys.argv[1:]:
port = int(sys.argv[1])
else:
port = 8000
server_address = ('127.0.0.1', port)
HandlerClass.protocol_version = Protocol
httpd = ServerClass(server_address, HandlerClass)
sa = httpd.socket.getsockname()
print "Serving HTTP on", sa[0], "port", sa[1], "..."
httpd.serve_forever()