Python Language Find All Non-Overlapping Matches


Example

re.findall(r"[0-9]{2,3}", "some 1 text 12 is 945 here 4445588899")
# Out: ['12', '945', '444', '558', '889']

Note that the r before "[0-9]{2,3}" tells python to interpret the string as-is; as a "raw" string.

You could also use re.finditer() which works in the same way as re.findall() but returns an iterator with SRE_Match objects instead of a list of strings:

results = re.finditer(r"([0-9]{2,3})", "some 1 text 12 is 945 here 4445588899")
print(results)
# Out: <callable-iterator object at 0x105245890>
for result in results:
     print(result.group(0))
''' Out:
12
945
444
558
889
'''