int a = 6; // 0110b (0x06)
int b = 10; // 1010b (0x0A)
int c = a & b; // 0010b (0x02)
std::cout << "a = " << a << ", b = " << b << ", c = " << c << std::endl;
Output
a = 6, b = 10, c = 2
Why
A bit wise AND
operates on the bit level and uses the following Boolean truth table:
TRUE AND TRUE = TRUE
TRUE AND FALSE = FALSE
FALSE AND FALSE = FALSE
When the binary value for a
(0110
) and the binary value for b
(1010
) are AND
'ed together we get the binary value of 0010
:
int a = 0 1 1 0
int b = 1 0 1 0 &
---------
int c = 0 0 1 0
The bit wise AND does not change the value of the original values unless specifically assigned to using the bit wise assignment compound operator &=
:
int a = 5; // 0101b (0x05)
a &= 10; // a = 0101b & 1010b