This example shows the basic type inferences the compiler can perform.
auto a = 1; // a = int
auto b = 2u; // b = unsigned int
auto c = &a; // c = int*
const auto d = c; // d = const int*
const auto& e = b; // e = const unsigned int&
auto x = a + b // x = int, #compiler warning unsigned and signed
auto v = std::vector<int>; // v = std::vector<int>
However, the auto keyword does not always perform the expected type inference without additional hints for &
or const
or constexpr
// y = unsigned int,
// note that y does not infer as const unsigned int&
// The compiler would have generated a copy instead of a reference value to e or b
auto y = e;