C++ Tutorial => Turn a sequence of indices into copies of an element

Example

Expanding the parameter pack of indices in a comma expression with a value creates a copy of the value for each of the indices. Sadly, gcc and clang think the index has no effect and warn about it (gcc can be silenced by casting the index to void):

#include <algorithm>
#include <array>
#include <iostream>
#include <iterator>
#include <string>
#include <utility>

template <typename T, std::size_t... I>
std::array<T, sizeof...(I)> make_array(T const& value, std::index_sequence<I...>) {
    return std::array<T, sizeof...(I)>{ (I, value)... };
}

template <int N, typename T>
std::array<T, N> make_array(T const& value) {
    return make_array(value, std::make_index_sequence<N>());
}

int main() {
    auto array = make_array<20>(std::string("value"));
    std::copy(array.begin(), array.end(),
              std::ostream_iterator<std::string>(std::cout, " "));
    std::cout << "\n";
}

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C++ std::integer_sequence Turn a sequence of indices into copies of an element

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