Java Language Tutorial => Expression evaluation order

Example

Java expressions are evaluated following the following rules:

In the following example:

int i = method1() + method2();

the order of evaluation is:

Note that if the effects of the calls are observable, you will be able to observe that the call to method1 occurs before the call to method2.

In the following example:

int i = 1;
intArray[i] = ++i + 1;

the order of evaluation is:

The left operand of = operator is evaluated. This gives the address of intArray[1].
The pre-increment is evaluated. This adds 1 to i, and evaluates to 2.
The right hand operand of the + is evaluated.
The + operation is evaluated to: 2 + 1 -> 3.
The = operation is evaluated, assigning 3 to intArray[1].

Note that since the left-hand operand of the = is evaluated first, it is not influenced by the side-effect of the ++i subexpression.

Reference:

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